中文XML论坛--这个要求怎么写？？？新手求救

贴子主题：这个要求怎么写？？？新手求救

本主题类别:

请问，怎么样来写才可以实现我的要求？？
#######################################
<?xml version="1.0" encoding="UTF-8"?>
<service class="org.lwap.application.FormBasedService" xmlns:jsp="http://mvc.lwap.org/builder/jsp" xmlns:std="http://mvc.lwap.org/default" login-required="true" default-dispatch="WorkflowPersonalActiveList.service?menu_id=10002&menu_title=工作流处理" target-type="service" dispatch-style="redirect">
######################################
<view>
  
    if ${/session/@user_id}=1282 then
    <jsp:textlabel Prompt="您无申请的权限，请于相关人员联系"/>
  <jsp:button Type="image" Prompt="保存" Name="save" OnClick="" />

else
  <jsp:form Entity="CARLOAN_APPLY" Align="center" Width="95%" SubmitPrompt="提交">
   <jsp:form-section Prompt="主管资格审批">
    <jsp:input Type="value-selector" DataType="java.lang.Integer" Name="PROPOSER" dataField="@EMPLOYEE_ID" displayField="@NAME" Prompt="员工姓名" Width="100" Height="16" HRef="EmployeeSelect.service" Nullable="false"/>
    <jsp:input Type="textedit" Name="JOBNAME" Prompt="部门职位" Nullable="false"/>
    <jsp:input Type="textarea" Name="DESCRIPTION" Cols="60" Rows="8" Prompt="审批意见" Nullable="false"/>
   </jsp:form-section>
  </jsp:form>

</view>

<action>
  <query Sql="select HANDWF_CARLOAN_APP_s.nextval as id from dual" ElementName="pk"/>
  <update Sql="begin
                if ${/session/@user_id}=1282 then
                insert into handwf_carloan_app
        (  instance_id ,
                       employee_id ,
                       proposer,
                       job_name,
                       description ,
                       submit_date
       )
         values
          (  ${/model/pk/@ID},
          ${/session/@user_id},
      ${@PROPOSER},
      ${@JOBNAME},
      ${@DESCRIPTION} ,
      sysdate
      );
                   wfl_core.workflow_instance_create_p( 10209 , ${/session/@user_id} , ${/model/pk/@ID}  );
                   end if;
                   end;"/>
</action>
</service>
#################################################


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